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In this question the general formula p(a|b) = p(a ∩ b)/p(b) is used 1st 2nd boy girl boy seen boy boy boy seen girl boy the net effect is that even if i don't know which one is definitely a boy, the other child can only be a girl or a boy and that is always and only a 1/2 probability (ignoring any biological weighting that girls may represent 51% of births or whatever the reality is). I understand through intuition why the answer should be 1/3
Good girls finish the job on their face : paleeyedgirls
What i don't understand is why p(both girls, at least one girl) is. An unreasonable rule would be one in which the expected children per couple was infinite. Considering the population of girls with tastes disorders, i do a binomial test with number of success k = 7, number of trials n = 8, and probability of success p = 0.5, to test my null hypothesis h0 = my cake tastes good for no more than.
A couple decides to keep having children until they have at least one boy and at least one girl, and then stop
Assume they never have twi. The other possibilities—two boys or two girls—have probabilities 1/4 and 1/4 Suppose i ask him whether he has any boys, and he says yes What is the probability that one child is a girl
Suppose instead that i happen to see one of his children run by, and it is a boy What is the probability that the other child is a girl In how many different ways can 5 people sit around a round table Is the symmetry of the table important
If the symmetry of the table is not taken into account the.
Use standard type for greek letters, subscripts and superscripts that function as identifiers (i.e., are not variables, as in the subscript “girls” in the example that follows), and abbreviations that are not variables (e.g., log, glm, wls) Use bold type for symbols for vectors and matrices Use italic type for all other statistical symbols. A couple decides to keep having children until they have the same number of boys and girls, and then stop
Assume they never have twins, that the trials are independent with probability 1/2 of a boy, and that they are fertile enough to keep producing children indefinitely. Expected girls from one couple$ {}=0.5\cdot1 + 0.25\cdot1 =0.75$ expected boys from one couple$ {}=0.25\cdot1 + 0.25\cdot2 =0.75$ 1 as i said this works for any reasonable rule that could exist in the real world
